70. Climbing Stairs #
题目 #
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
Example 1:
Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps
Example 2:
Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step
题目大意 #
假设你正在爬楼梯。需要 n 阶你才能到达楼顶。每次你可以爬 1 或 2 个台阶。你有多少种不同的方法可以爬到楼顶呢?注意:给定 n 是一个正整数
解题思路 #
- 简单的 DP,经典的爬楼梯问题。一个楼梯可以由
n-1
和n-2
的楼梯爬上来。 - 这一题求解的值就是斐波那契数列。
代码 #
package leetcode
func climbStairs(n int) int {
dp := make([]int, n+1)
dp[0], dp[1] = 1, 1
for i := 2; i <= n; i++ {
dp[i] = dp[i-1] + dp[i-2]
}
return dp[n]
}