0070. Climbing Stairs

70. Climbing Stairs #

题目 #

You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

Note: Given n will be a positive integer.

Example 1:

Input: 2
Output: 2
Explanation: There are two ways to climb to the top.
1. 1 step + 1 step
2. 2 steps

Example 2:

Input: 3
Output: 3
Explanation: There are three ways to climb to the top.
1. 1 step + 1 step + 1 step
2. 1 step + 2 steps
3. 2 steps + 1 step

题目大意 #

假设你正在爬楼梯。需要 n 阶你才能到达楼顶。每次你可以爬 1 或 2 个台阶。你有多少种不同的方法可以爬到楼顶呢?注意:给定 n 是一个正整数

解题思路 #

  • 简单的 DP,经典的爬楼梯问题。一个楼梯可以由 n-1n-2 的楼梯爬上来。
  • 这一题求解的值就是斐波那契数列。

代码 #


package leetcode

func climbStairs(n int) int {
	dp := make([]int, n+1)
	dp[0], dp[1] = 1, 1
	for i := 2; i <= n; i++ {
		dp[i] = dp[i-1] + dp[i-2]
	}
	return dp[n]
}


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