0112. Path Sum

112. Path Sum #

题目 #

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

Note: A leaf is a node with no children.

Example:

Given the below binary tree and sum = 22,

      5
     / \
    4   8
   /   / \
  11  13  4
 /  \      \
7    2      1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

题目大意 #

给定一个二叉树和一个目标和,判断该树中是否存在根节点到叶子节点的路径,这条路径上所有节点值相加等于目标和。说明: 叶子节点是指没有子节点的节点。

解题思路 #

  • 递归求解即可

代码 #


package leetcode

/**
 * Definition for a binary tree node.
 * type TreeNode struct {
 *     Val int
 *     Left *TreeNode
 *     Right *TreeNode
 * }
 */
func hasPathSum(root *TreeNode, sum int) bool {
	if root == nil {
		return false
	}
	if root.Left == nil && root.Right == nil {
		return sum == root.Val
	}
	return hasPathSum(root.Left, sum-root.Val) || hasPathSum(root.Right, sum-root.Val)
}


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Calendar Sep 6, 2020
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