0148. Sort List

148. Sort List #

题目 #

Sort a linked list in O(n log n) time using constant space complexity.

Example 1:


Input: 4->2->1->3
Output: 1->2->3->4

Example 2:


Input: -1->5->3->4->0
Output: -1->0->3->4->5

题目大意 #

链表的排序,要求时间复杂度必须是 O(n log n),空间复杂度是 O(1)

解题思路 #

这道题只能用归并排序才能符合要求。归并排序需要的 2 个操作在其他题目已经出现过了,取中间点是第 876 题,合并 2 个有序链表是第 21 题。

代码 #


package leetcode

/**
 * Definition for singly-linked list.
 * type ListNode struct {
 *     Val int
 *     Next *ListNode
 * }
 */
func sortList(head *ListNode) *ListNode {
	length := 0
	cur := head
	for cur != nil {
		length++
		cur = cur.Next
	}
	if length <= 1 {
		return head
	}

	middleNode := middleNode1(head)
	cur = middleNode.Next
	middleNode.Next = nil
	middleNode = cur

	left := sortList(head)
	right := sortList(middleNode)
	return mergeTwoLists148(left, right)
}

func middleNode1(head *ListNode) *ListNode {
	if head == nil || head.Next == nil {
		return head
	}
	p1 := head
	p2 := head
	for p2.Next != nil && p2.Next.Next != nil {
		p1 = p1.Next
		p2 = p2.Next.Next
	}
	return p1
}

func mergeTwoLists148(l1 *ListNode, l2 *ListNode) *ListNode {
	if l1 == nil {
		return l2
	}
	if l2 == nil {
		return l1
	}
	if l1.Val < l2.Val {
		l1.Next = mergeTwoLists(l1.Next, l2)
		return l1
	}
	l2.Next = mergeTwoLists(l1, l2.Next)
	return l2
}


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