211. Design Add and Search Words Data Structure #
题目 #
Design a data structure that supports the following two operations:
void addWord(word)
bool search(word)
search(word) can search a literal word or a regular expression string containing only letters a-z
or .
. A .
means it can represent any one letter.
Example:
addWord("bad")
addWord("dad")
addWord("mad")
search("pad") -> false
search("bad") -> true
search(".ad") -> true
search("b..") -> true
Note: You may assume that all words are consist of lowercase letters a-z
.
题目大意 #
设计一个支持以下两种操作的数据结构:void addWord(word)
、bool search(word)
。search(word)
可以搜索文字或正则表达式字符串,字符串只包含字母 . 或 a-z 。 “.” 可以表示任何一个字母。
解题思路 #
- 设计一个
WordDictionary
的数据结构,要求具有addWord(word)
和search(word)
的操作,并且具有模糊查找的功能。 - 这一题是第 208 题的加强版,在第 208 题经典的 Trie 上加上了模糊查找的功能。其他实现一模一样。
代码 #
package leetcode
type WordDictionary struct {
children map[rune]*WordDictionary
isWord bool
}
/** Initialize your data structure here. */
func Constructor211() WordDictionary {
return WordDictionary{children: make(map[rune]*WordDictionary)}
}
/** Adds a word into the data structure. */
func (this *WordDictionary) AddWord(word string) {
parent := this
for _, ch := range word {
if child, ok := parent.children[ch]; ok {
parent = child
} else {
newChild := &WordDictionary{children: make(map[rune]*WordDictionary)}
parent.children[ch] = newChild
parent = newChild
}
}
parent.isWord = true
}
/** Returns if the word is in the data structure. A word could contain the dot character '.' to represent any one letter. */
func (this *WordDictionary) Search(word string) bool {
parent := this
for i, ch := range word {
if rune(ch) == '.' {
isMatched := false
for _, v := range parent.children {
if v.Search(word[i+1:]) {
isMatched = true
}
}
return isMatched
} else if _, ok := parent.children[rune(ch)]; !ok {
return false
}
parent = parent.children[rune(ch)]
}
return len(parent.children) == 0 || parent.isWord
}
/**
* Your WordDictionary object will be instantiated and called as such:
* obj := Constructor();
* obj.AddWord(word);
* param_2 := obj.Search(word);
*/