350. Intersection of Two Arrays II #

题目 #

Given two arrays, write a function to compute their intersection.

Example 1:

Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2,2]

Example 2:

Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [4,9]

Note:

• Each element in the result should appear as many times as it shows in both arrays.
• The result can be in any order.

Follow up:

• What if the given array is already sorted? How would you optimize your algorithm?
• What if nums1’s size is small compared to nums2’s size? Which algorithm is better?
• What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?

题目大意 #

这题是第 349 题的加强版。要求输出 2 个数组的交集元素，如果元素出现多次，要输出多次。

解题思路 #

这一题还是延续第 349 题的思路。把数组一中的数字都放进字典中，另外字典的 key 是数组中的数字，value 是这个数字出现的次数。在扫描数组二的时候，每取出一个存在的数组，把字典中的 value 减一。如果 value 是 0 代表不存在这个数字。

代码 #

package leetcode

func intersect(nums1 []int, nums2 []int) []int {
	m := map[int]int{}
	var res []int
	for _, n := range nums1 {
		m[n]++
	}
	for _, n := range nums2 {
		if m[n] > 0 {
			res = append(res, n)
			m[n]--
		}
	}
	return res
}