0306. Additive Number

306. Additive Number #

题目 #

Additive number is a string whose digits can form additive sequence.

A valid additive sequence should contain at least three numbers. Except for the first two numbers, each subsequent number in the sequence must be the sum of the preceding two.

Given a string containing only digits '0'-'9', write a function to determine if it’s an additive number.

Note: Numbers in the additive sequence cannot have leading zeros, so sequence 1, 2, 03 or 1, 02, 3 is invalid.

Example 1:

Input: "112358"
Output: true 
Explanation: The digits can form an additive sequence: 1, 1, 2, 3, 5, 8. 
             1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, 3 + 5 = 8

Example 2:

Input: "199100199"
Output: true 
Explanation: The additive sequence is: 1, 99, 100, 199. 
             1 + 99 = 100, 99 + 100 = 199

Follow up:How would you handle overflow for very large input integers?

题目大意 #

累加数是一个字符串,组成它的数字可以形成累加序列。一个有效的累加序列必须至少包含 3 个数。除了最开始的两个数以外,字符串中的其他数都等于它之前两个数相加的和。给定一个只包含数字 ‘0’-‘9’ 的字符串,编写一个算法来判断给定输入是否是累加数。说明: 累加序列里的数不会以 0 开头,所以不会出现 1, 2, 03 或者 1, 02, 3 的情况。

解题思路 #

  • 在给出的字符串中判断该字符串是否为斐波那契数列形式的字符串。
  • 由于每次判断需要累加 2 个数字,所以在 DFS 遍历的过程中需要维护 2 个数的边界,firstEndsecondEnd,两个数加起来的和数的起始位置是 secondEnd + 1。每次在移动 firstEndsecondEnd 的时候,需要判断 strings.HasPrefix(num[secondEnd + 1:], strconv.Itoa(x1 + x2)),即后面的字符串中是否以和为开头。
  • 如果第一个数字起始数字出现了 0 ,或者第二个数字起始数字出现了 0,都算非法异常情况,都应该直接返回 false。

代码 #


package leetcode

import (
	"strconv"
	"strings"
)

// This function controls various combinations as starting points
func isAdditiveNumber(num string) bool {
	if len(num) < 3 {
		return false
	}
	for firstEnd := 0; firstEnd < len(num)/2; firstEnd++ {
		if num[0] == '0' && firstEnd > 0 {
			break
		}
		first, _ := strconv.Atoi(num[:firstEnd+1])
		for secondEnd := firstEnd + 1; max(firstEnd, secondEnd-firstEnd) <= len(num)-secondEnd; secondEnd++ {
			if num[firstEnd+1] == '0' && secondEnd-firstEnd > 1 {
				break
			}
			second, _ := strconv.Atoi(num[firstEnd+1 : secondEnd+1])
			if recursiveCheck(num, first, second, secondEnd+1) {
				return true
			}
		}
	}
	return false
}

//Propagate for rest of the string
func recursiveCheck(num string, x1 int, x2 int, left int) bool {
	if left == len(num) {
		return true
	}
	if strings.HasPrefix(num[left:], strconv.Itoa(x1+x2)) {
		return recursiveCheck(num, x2, x1+x2, left+len(strconv.Itoa(x1+x2)))
	}
	return false
}


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