0495. Teemo Attacking

# 495. Teemo Attacking#

## 题目 #

Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration seconds.

More formally, an attack at second t will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1].

If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration seconds after the new attack.

You are given a non-decreasing integer array timeSeries, where timeSeries[i] denotes that Teemo attacks Ashe at second timeSeries[i], and an integer duration.

Return the total number of seconds that Ashe is poisoned.

Example 1:

``````Input: timeSeries = [1,4], duration = 2
Output: 4
Explanation: Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5.
Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total.
``````

Example 2:

``````Input: timeSeries = [1,2], duration = 2
Output: 3
Explanation: Teemo's attacks on Ashe go as follows:
- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2.
- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3.
Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total.
``````

Constraints:

• 1 <= timeSeries.length <= 10000
• 0 <= timeSeries[i], duration <= 10000000
• timeSeries is sorted in non-decreasing order.

## 解题思路 #

• i 从 1 开始计数，令 t 等于 timeSeries[i - 1]
• 比较 end(t + duration - 1) 和 timeSeries[i] 的大小，
• 如果 end 小于 timeSeries[i],ans+=duration
• 否则 ans += timeSeries[i] - t
• ans += duration 并返回 ans

## 代码 #

``````
package leetcode

func findPoisonedDuration(timeSeries []int, duration int) int {
var ans int
for i := 1; i < len(timeSeries); i++ {
t := timeSeries[i-1]
end := t + duration - 1
if end < timeSeries[i] {
ans += duration
} else {
ans += timeSeries[i] - t
}
}
ans += duration
return ans
}

`````` Apr 8, 2023 Edit this page