0946. Validate Stack Sequences

946. Validate Stack Sequences #

题目 #

Given two sequences pushed and popped with distinct values, return true if and only if this could have been the result of a sequence of push and pop operations on an initially empty stack.

Example 1:


Input: pushed = [1,2,3,4,5], popped = [4,5,3,2,1]
Output: true
Explanation: We might do the following sequence:
push(1), push(2), push(3), push(4), pop() -> 4,
push(5), pop() -> 5, pop() -> 3, pop() -> 2, pop() -> 1

Example 2:


Input: pushed = [1,2,3,4,5], popped = [4,3,5,1,2]
Output: false
Explanation: 1 cannot be popped before 2.

Note:

  1. 0 <= pushed.length == popped.length <= 1000
  2. 0 <= pushed[i], popped[i] < 1000
  3. pushed is a permutation of popped.
  4. pushed and popped have distinct values.

题目大意 #

给 2 个数组,一个数组里面代表的是 push 的顺序,另一个数组里面代表的是 pop 的顺序。问按照这样的顺序操作以后,最终能否把栈清空?

解题思路 #

这一题也是靠栈操作的题目,按照 push 数组的顺序先把压栈,然后再依次在 pop 里面找栈顶元素,找到了就 pop,直到遍历完 pop 数组,最终如果遍历完了 pop 数组,就代表清空了整个栈了。

代码 #


package leetcode

import "fmt"

func validateStackSequences(pushed []int, popped []int) bool {
	stack, j, N := []int{}, 0, len(pushed)
	for _, x := range pushed {
		stack = append(stack, x)
		fmt.Printf("stack = %v j = %v\n", stack, j)
		for len(stack) != 0 && j < N && stack[len(stack)-1] == popped[j] {
			stack = stack[0 : len(stack)-1]
			j++
		}
		fmt.Printf("*****stack = %v j = %v\n", stack, j)
	}
	return j == N
}


⬅️上一页

下一页➡️

Calendar Sep 6, 2020
Edit Edit this page
本站总访问量:  次 您是本站第  位访问者