1295. Find Numbers With Even Number of Digits

1295. Find Numbers with Even Number of Digits#

题目 #

Given an array `nums` of integers, return how many of them contain an even number of digits.

Example 1:

``````Input: nums = [12,345,2,6,7896]
Output: 2
Explanation:
12 contains 2 digits (even number of digits).
345 contains 3 digits (odd number of digits).
2 contains 1 digit (odd number of digits).
6 contains 1 digit (odd number of digits).
7896 contains 4 digits (even number of digits).
Therefore only 12 and 7896 contain an even number of digits.
``````

Example 2:

``````Input: nums = [555,901,482,1771]
Output: 1
Explanation:
Only 1771 contains an even number of digits.
``````

Constraints:

• `1 <= nums.length <= 500`
• `1 <= nums[i] <= 10^5`

题目大意 #

• 1 <= nums.length <= 500
• 1 <= nums[i] <= 10^5

解题思路 #

• 给你一个整数数组，要求输出位数为偶数的数字的个数。
• 简单题，把每个数字转换为字符串判断长度是否是偶数即可。

代码 #

``````func findNumbers(nums []int) int {
res := 0
for _, n := range nums {
res += 1 - len(strconv.Itoa(n))%2
}
return res
}
``````

Apr 8, 2023