1317. Convert Integer to the Sum of Two No Zero Integers

1317. Convert Integer to the Sum of Two No-Zero Integers #

题目 #

Given an integer n. No-Zero integer is a positive integer which doesn’t contain any 0 in its decimal representation.

Return a list of two integers [A, B] where:

  • A and B are No-Zero integers.
  • A + B = n

It’s guarateed that there is at least one valid solution. If there are many valid solutions you can return any of them.

Example 1:

Input: n = 2
Output: [1,1]
Explanation: A = 1, B = 1. A + B = n and both A and B don't contain any 0 in their decimal representation.

Example 2:

Input: n = 11
Output: [2,9]

Example 3:

Input: n = 10000
Output: [1,9999]

Example 4:

Input: n = 69
Output: [1,68]

Example 5:

Input: n = 1010
Output: [11,999]

Constraints:

  • 2 <= n <= 10^4

题目大意 #

「无零整数」是十进制表示中 不含任何 0 的正整数。给你一个整数 n,请你返回一个 由两个整数组成的列表 [A, B],满足:

  • A 和 B 都是无零整数
  • A + B = n

题目数据保证至少有一个有效的解决方案。如果存在多个有效解决方案,你可以返回其中任意一个。

解题思路 #

  • 给定一个整数 n,要求把它分解为 2 个十进制位中不含 0 的正整数且这两个正整数之和为 n。
  • 简单题。在 [1, n/2] 区间内搜索,只要有一组满足条件的解就 break。题目保证了至少有一组解,并且多组解返回任意一组即可。

代码 #


package leetcode

func getNoZeroIntegers(n int) []int {
	noZeroPair := []int{}
	for i := 1; i <= n/2; i++ {
		if isNoZero(i) && isNoZero(n-i) {
			noZeroPair = append(noZeroPair, []int{i, n - i}...)
			break
		}
	}
	return noZeroPair
}

func isNoZero(n int) bool {
	for n != 0 {
		if n%10 == 0 {
			return false
		}
		n /= 10
	}
	return true
}


⬅️上一页

下一页➡️

Calendar Sep 6, 2020
Edit Edit this page
本站总访问量:  次 您是本站第  位访问者