1038. Binary Search Tree to Greater Sum Tree #
Problem #
Given the root of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.
As a reminder, a binary search tree is a tree that satisfies these constraints:
- The left subtree of a node contains only nodes with keys less than the node’s key.
- The right subtree of a node contains only nodes with keys greater than the node’s key.
- Both the left and right subtrees must also be binary search trees.
Note: This question is the same as 538: https://leetcode.com/problems/convert-bst-to-greater-tree/
Example 1:

Input: root = [4,1,6,0,2,5,7,null,null,null,3,null,null,null,8]
Output: [30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]
Example 2:
Input: root = [0,null,1]
Output: [1,null,1]
Example 3:
Input: root = [1,0,2]
Output: [3,3,2]
Example 4:
Input: root = [3,2,4,1]
Output: [7,9,4,10]
Constraints:
- The number of nodes in the tree is in the range
[1, 100]. 0 <= Node.val <= 100- All the values in the tree are unique.
rootis guaranteed to be a valid binary search tree.
Problem Summary #
Given the root node of a binary search tree whose node values are all distinct, convert it to a Greater Sum Tree such that the new value of each node node is equal to the sum of values greater than or equal to node.val in the original tree.
As a reminder, a binary search tree satisfies the following constraints:
- The left subtree of a node contains only nodes with keys less than the node’s key.
- The right subtree of a node contains only nodes with keys greater than the node’s key.
- Both the left and right subtrees must also be binary search trees.
Solution Approach #
- Based on the ordered property of a binary search tree, to convert it to a Greater Sum Tree, simply traverse in the order of right node - root node - left node, and accumulate the sum.
- This problem is the same as problem 538.
Code #
package leetcode
import (
"github.com/halfrost/leetcode-go/structures"
)
// TreeNode define
type TreeNode = structures.TreeNode
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func bstToGst(root *TreeNode) *TreeNode {
if root == nil {
return root
}
sum := 0
dfs1038(root, &sum)
return root
}
func dfs1038(root *TreeNode, sum *int) {
if root == nil {
return
}
dfs1038(root.Right, sum)
root.Val += *sum
*sum = root.Val
dfs1038(root.Left, sum)
}