1154. Day of the Year #
Problem #
Given a string date representing a
Gregorian calendar date formatted as YYYY-MM-DD, return the day number of the year.
Example 1:
Input: date = "2019-01-09"
Output: 9
Explanation: Given date is the 9th day of the year in 2019.
Example 2:
Input: date = "2019-02-10"
Output: 41
Example 3:
Input: date = "2003-03-01"
Output: 60
Example 4:
Input: date = "2004-03-01"
Output: 61
Constraints:
date.length == 10date[4] == date[7] == '-', and all otherdate[i]'s are digitsdaterepresents a calendar date between Jan 1st, 1900 and Dec 31, 2019.
Problem Summary #
Implement a class MajorityChecker that should have the following APIs:
- MajorityChecker(int[] arr) constructs an instance of MajorityChecker with the given array arr.
- int query(int left, int right, int threshold) has the following parameters:
- 0 <= left <= right < arr.length represents the length of the subarray of array arr.
- 2 * threshold > right - left + 1, meaning the threshold threshold is always greater than half the length of the subsequence.
Each query query(…) returns the element that appears at least threshold times in arr[left], arr[left+1], …, arr[right]; if no such element exists, return -1.
Notes:
- 1 <= arr.length <= 20000
- 1 <= arr[i] <= 20000
- For each query, 0 <= left <= right < len(arr)
- For each query, 2 * threshold > right - left + 1
- The maximum number of queries is 10000
Solution Approach #
- Given a time string, find which day of the year this day is.
- Easy problem. Just handle it according to the problem statement.
Code #
package leetcode
import "time"
func dayOfYear(date string) int {
first := date[:4] + "-01-01"
firstDay, _ := time.Parse("2006-01-02", first)
dateDay, _ := time.Parse("2006-01-02", date)
duration := dateDay.Sub(firstDay)
return int(duration.Hours())/24 + 1
}